2x^2-22=-4x

Solution for 2x^2-22=-4x equation:

2x^2-22=-4x

We move all terms to the left:

2x^2-22-(-4x)=0

We get rid of parentheses

2x^2+4x-22=0

a = 2; b = 4; c = -22;
Δ = b2-4ac
Δ = 42-4·2·(-22)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{3}}{2*2}=\frac{-4-8\sqrt{3}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{3}}{2*2}=\frac{-4+8\sqrt{3}}{4}
$